20=100-20x+3x^2

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Solution for 20=100-20x+3x^2 equation: 



20=100-20x+3x^2

We move all terms to the left:

20-(100-20x+3x^2)=0

We get rid of parentheses

-3x^2+20x-100+20=0

We add all the numbers together, and all the variables

-3x^2+20x-80=0

a = -3; b = 20; c = -80;
Δ = b2-4ac
Δ = 202-4·(-3)·(-80)
Δ = -560
Delta is less than zero, so there is no solution for the equation

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